brute-force attack in python

In a brute-force attack, the advisory attempts to decrypt the ciphertext by using every possible key. If the key is small enough, a brute-force attack can be successful in a matter of minutes. In fact, if the keys are around 222, we can write a Python script to crack the password utilizing brute force. For your estimation purposes, when it comes to brute-force attacks, the following helps you ballpark
the amount of security you get for various size problems:

• A key space/message space of 264 is enough for a couple hours of security.
• A key space/message space of 2128 is enough for several decades of pre- quantum security.
• A key space/message space of 2256 is enough for several decades of post- quantum security.

The following is an example of code that will generate a four-digit PIN and then loop through the iterations using brute force to determine the password:

┌──(hackerboy㉿KumarAtulJaiswal)-[~/Desktop/implementing-cryptography/cert]
└─$ cat brute-crypt.py     
#!/usr/bin/python3

import random
generated_password = str(random.randint(0, 9999))
#print(generated_password)

for i in range(10000):
    Trial = str(i)
    if Trial == generated_password:
       print('Found password: ' + generated_password)
                                                                                                                                                                        
┌──(hackerboy㉿KumarAtulJaiswal)-[~/Desktop/implementing-cryptography/cert]
└─$ 

┌──(hackerboy㉿KumarAtulJaiswal)-[~/Desktop/implementing-cryptography/cert]
└─$ 
                                                                                                                                                                        
┌──(hackerboy㉿KumarAtulJaiswal)-[~/Desktop/implementing-cryptography/cert]
└─$ python3 brute-crypt.py 
Found password: 8737
                                                                                                                                                                        
┌──(hackerboy㉿KumarAtulJaiswal)-[~/Desktop/implementing-cryptography/cert]
└─$ python3 brute-crypt.py
Found password: 6227
                                                                                                                                                                        
┌──(hackerboy㉿KumarAtulJaiswal)-[~/Desktop/implementing-cryptography/cert]
└─$ python3 brute-crypt.py
Found password: 433
                                                                                                                                                                        
┌──(hackerboy㉿KumarAtulJaiswal)-[~/Desktop/implementing-cryptography/cert]
└─$ 

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